Question

Will get MEDAL!!!

Answer 1

what are the zeros of the function f(x)=(3x^2-3x-6)/(3x-6)
–1

1

2

–2
I am stuck with A or C

Answer 2

Start by factoring the top and the bottom. From the top, all the terms have a 3 as a factor, so you can factor out a 3. From the bottom, both terms also contain 3 as a factor, so you can factor out a 3 from the denominator as well

Answer 3

Ok

Answer 4

Then you need to cancel out the 3 from top and bottom and factor the X^2-x-2 into the form (x + ?) (x + ?)

Answer 5

So you have (x-2) * (x+1) / (x +2)

Answer 6

Sorry we have (x-2) * (x+1) / (x - 2)
So the x-2 can cancel out and leave the x+1 with a hole at 2
So the zero is x = -1