Determine the domain of the function. f(x) = 4 / x^2
Decision and reason.
I do not know haha
What will make the denominator 0?
first think about what a domain is..... that might help a little
Recall that you can't divide by zero. So start by setting your denominator equal to zero is a good place to start
a domain is all values of x where the function does exist... basically you cannot have a 0 in the denominator
then like @vinnv226 said.... set your denominator equal to 0 and that will tell you what value makes the denomintor zero and therefore makes the function for that value of x not exist.... so this number is not part of the domain because it cannot be
@lornbeach You know the drill, you have to say something.
where denominator not =0
Haha drill ? Uhm okay so x^2 = 0
That's a start... so, for what values of x would \[x^2=0\]?
0
And nothing else?
could it be x greater than or equal to 0
It's just 0. @terenzreignz You're a terror!
No... I'm thorough :)
Brother's got rhymes too.
@lornbeach So, everything but 0 is in the domain.
all real numbers except for 0
boo yah
thank you, everyone !
See this, the graph starts acting crazy as it goes to zero. https://www.google.com/search?q=4%2Fx%5E2&oq=4%2Fx%5E2&aqs=chrome.0.69i57j69i58j0l3j69i62.2888j0&sourceid=chrome&ie=UTF-8
Yes I see it ! Thanks @primeralph ((:
That's crazy? THIS is crazy.... https://www.google.com/search?q=4%2Fx%5E2&oq=4%2Fx%5E2&aqs=chrome.0.69i57j69i58j0l3j69i62.2888j0&sourceid=chrome&ie=UTF-8#sclient=psy-ab&q=sin(1%2Fx)&oq=sin(1%2Fx)&gs_l=serp.3..0l4.9102.10379.1.10707.8.7.0.1.1.0.206.1114.0j6j1.7.0....0.0..1c.1.20.psy-ab.EMP36IZHIrQ&pbx=1&bav=on.2,or.r_qf.&bvm=bv.49967636%2Cd.dGI%2Cpv.xjs.s.en_US.jOYpRJj4zMA.O&fp=f5a1e0105e9cf76&biw=1366&bih=667 :3 Not that this is relevant in any manner :D
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