Question

solve (2x^3-4x^2+3)+(x^2-3x^2+1)

Answer 1

add them! :)

Answer 2

idk how to :C

Answer 3

what is \(3+1\) ?

Answer 4

4

Answer 5

btw is it really \( (2x^3-4x^2+3)+(x^2-3x^2+1)
\) or perhaps \( (2x^3-4x^2+3)+(x^3-3x^2+1)
\)

Answer 6

you see the difference? does the second one have two square terms \(x^2\) and \(-x^2\) or does it have a cube term \(x^3\) and a square term \(-2x^2\) ?

Answer 7

is the first one that you posted

Answer 8

i am going to guess it is
\[(2x^3-4x^2+3)+(x^3-3x^2+1)\] am i right?

Answer 9

yup thats it

Answer 10

ok lets go slow (but not too slow)

Answer 11

lol ok :)

Answer 12

we already decided that \(3+1=4\) so that will be the number out at the end

Answer 13

yup i got that part

Answer 14

like terms have the same exponent, so we have like terms of \(x^3\) and \(2x^3\)

Answer 15

and just like \(1000+2000=3000\) or one apple and two apples is three apples, we get
\[x^3+2x^3=3x^3\]

Answer 16

so far so good?

Answer 17

so u dont add the exponents?

Answer 18

hell no
i was just about to say don't screw around with the exponents when you are adding
that is for when you multiply

Answer 19

ok so then what ?

Answer 20

look at my first example \(1000+2000=3000\) i put it there on purpose, because \(1000=10^3\) and \(2000=2\times 10^3\) and \(10^3+2\times 10^3=3\times 10^3\) powers stay the same don't change them!!

Answer 21

oh ok i got it

Answer 22

so finally we get \(-4x^2-3x^2\)

Answer 23

any guesses?

Answer 24

-7x^2?

Answer 25

you got it !

Answer 26

final answer:
\[\large 3x^3-7x^2+4\]

Answer 27

omg thats what i got yay ok i got it i think i understand now C:

Answer 28

that wasn't that bad, right?

Answer 29

we can do another one if you like

Answer 30

it seems easy with your help :)

Answer 31

thanks

Answer 32

i got one

Answer 33

\[(5a-4b+3c) + (6a-4b+2c)\] @satellite73

Answer 34

ok like terms are the ones with the same letter

Answer 35

you do this mostly with your eyes
\[5a+6a=?\]

Answer 36

11a

Answer 37

k good,
on to the next one \(-4b-4b=?\)

Answer 38

-8b

Answer 39

k
next \(3c+2c=?\)

Answer 40

omg okay so i got this one but idk how to do this other one you think we could move to the other one ? pleaseeee

Answer 41

sure why not

Answer 42

okay i always have troublee with this (x+2) (x-2)

Answer 43

you have to do four multiplications
1) \(x\times x=x^2\)
2) \(2\times x=2x\)
3) \(-2\times x=-2x\)
4) \(2\times -2=-4\)

Answer 44

you get
\[x^2+2x-2x-4=x^2-4\]

Answer 45

oh omg now i get it aw thanks for all your help C:

Answer 46

yw
btw with practice you will see that \((a+b)(a-b)=a^2-b^2\) always, so \((x+2)(x-2)=x^2-4\) will come right away

Answer 47

oh ok omg @satellite73 one more please please please it iwll be the last one i promise ?

Answer 48

no problem, just ask

Answer 49

ok so how would you solve this -2x^4(3x^2-5x)

Answer 50

you mean multiply right?

Answer 51

\[ -2x^4(3x^2-5x)
\]
\[=-2x^4\times 3x^2+2x^4\times 5x\] now this is where you add the exponents

Answer 52

you should get
\[-6x^6+10x^5\]

Answer 53

-6x^6+10x^5

Answer 54

yes you go it!

Answer 55

yay

Answer 56

not too bad...

Answer 57

thanks c: i know im slow sorry :C