square root of -9 all over (
3-2)i + (1+5i)

Question

square root of -9 all over (
3-2)i + (1+5i)

anonymous · Answer

$$\bf \frac{ \sqrt{-9} }{ 3-2i+1+5i }=\frac{ \sqrt{-1} \sqrt{9} }{3-2i+1+5i }$$Note that complex numbers follow all the same laws with addition and other operations like real numbers hence you can add like terms in the denominators just the way you would with real numbers have 'i' been a real variable. Also re-call $\bf \sqrt{-1}=i$. Now I'll leave the simplifying to you :D @NickiSilva17

anonymous · Answer

@NickiSilva17 Can you simplify or do you require further help?

anonymous · Answer

Futher help please just started learning this so im practicing

anonymous · Answer

and thanks for your help

anonymous · Answer

more help pls

usukidoll · Answer

combine like terms on the bottom of the denominator

anonymous · Answer

is the answer 12-9i over 7?

usukidoll · Answer

|dw:1375346988576:dw| I got this