Question

help pleasee @Krishnadas @primeralph @surjithayer

Answer 1

centered at (-1,-3)..okay

Answer 2

\[((x-h)^2)/a^2 +((y-k)^2)/b^2 =1\]

Answer 3

yes

Answer 4

a=6 and b=4

Answer 5

so i basically plug it in

Answer 6

h=-1 and k=-3

Answer 7

\[\frac{ \left( x+1 \right)^{2} }{ 3^{2} }+\frac{ \left( y+3 \right)^{2} }{ 2^{2} }=1\]

Answer 8

@divagirl421 yes

Answer 9

@surjithayer 3^2 and 2^2?

Answer 10

thank you @Krishnadas

Answer 11

okay..:D

Answer 12

yw

Answer 13

how?

Answer 14

and also @surjithayer :)

Answer 15

oh so radius will be half of it...

Answer 16

yes

Answer 17

ooooooooo

Answer 18

@divagirl421 the equation by @surjithayer is right..I forgot to take the half

Answer 19

no doubt..

Answer 20

a nd b are radius what we have is diameter