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Mathematics 25 Online
OpenStudy (anonymous):

help pleasee @Krishnadas @primeralph @surjithayer

OpenStudy (anonymous):

OpenStudy (anonymous):

centered at (-1,-3)..okay

OpenStudy (anonymous):

\[((x-h)^2)/a^2 +((y-k)^2)/b^2 =1\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

a=6 and b=4

OpenStudy (anonymous):

so i basically plug it in

OpenStudy (anonymous):

h=-1 and k=-3

OpenStudy (anonymous):

\[\frac{ \left( x+1 \right)^{2} }{ 3^{2} }+\frac{ \left( y+3 \right)^{2} }{ 2^{2} }=1\]

OpenStudy (anonymous):

@divagirl421 yes

OpenStudy (anonymous):

@surjithayer 3^2 and 2^2?

OpenStudy (anonymous):

thank you @Krishnadas

OpenStudy (anonymous):

okay..:D

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

and also @surjithayer :)

OpenStudy (anonymous):

|dw:1375376194865:dw|

OpenStudy (anonymous):

oh so radius will be half of it...

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ooooooooo

OpenStudy (anonymous):

@divagirl421 the equation by @surjithayer is right..I forgot to take the half

OpenStudy (anonymous):

no doubt..

OpenStudy (anonymous):

a nd b are radius what we have is diameter

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