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Mathematics 18 Online
OpenStudy (anonymous):

Gabriel needs to purchase baseballs and bats for his youth baseball league. He’ll need at least 20 pieces of equipment, but he only has $525 to spend. Baseballs cost $20 each and bats cost $35 each. If Gabriel wants to purchase the most amount of equipment and still stay within his budget, which combination of baseballs and bats is optimal? (19, 1) (21, 3) (14, 7) (16, 4) http://learn.flvs.net/webdav/assessment_images/educator_advalgebra_v10/02_00_14.gif

OpenStudy (anonymous):

for this question your going to want to set up 2 equations and then solve the system

OpenStudy (anonymous):

let x=baseballs and y=bats. he can purchase 20 pieces of equipment therefore: x+y=20

OpenStudy (anonymous):

now the price of baseballs=$20 while bats=$35. he can only spend $525, so: 20x+35y=525.

OpenStudy (anonymous):

So now you have two equations: x+y=20 20x+35y=525

OpenStudy (anonymous):

oKAY SO do i plus in what?

OpenStudy (anonymous):

plug*

OpenStudy (anonymous):

each option to both equations and see which one gives me both?

OpenStudy (anonymous):

so either A or D?

OpenStudy (anonymous):

I think its C

OpenStudy (anonymous):

well since it is multiple choice. you can plug in the answers and see which one equals $525.

OpenStudy (anonymous):

im stuck between B and C? what do you think

OpenStudy (anonymous):

choice c would be the best because he will have maximized his budget of $525

OpenStudy (anonymous):

when i gave you the system of equations it would actually be x+y>or=20. because the question just says "at least 20 pices"

OpenStudy (anonymous):

okay so ill go with C

OpenStudy (anonymous):

could you help me with another one

OpenStudy (anonymous):

i wish i had time sorry ill be back in a little bit i have to go register for classes

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

yw!

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