Gabriel needs to purchase baseballs and bats for his youth baseball league. He’ll need at least 20 pieces of equipment, but he only has $525 to spend. Baseballs cost $20 each and bats cost $35 each. If Gabriel wants to purchase the most amount of equipment and still stay within his budget, which combination of baseballs and bats is optimal? (19, 1) (21, 3) (14, 7) (16, 4) http://learn.flvs.net/webdav/assessment_images/educator_advalgebra_v10/02_00_14.gif
for this question your going to want to set up 2 equations and then solve the system
let x=baseballs and y=bats. he can purchase 20 pieces of equipment therefore: x+y=20
now the price of baseballs=$20 while bats=$35. he can only spend $525, so: 20x+35y=525.
So now you have two equations: x+y=20 20x+35y=525
oKAY SO do i plus in what?
plug*
each option to both equations and see which one gives me both?
so either A or D?
I think its C
well since it is multiple choice. you can plug in the answers and see which one equals $525.
im stuck between B and C? what do you think
choice c would be the best because he will have maximized his budget of $525
when i gave you the system of equations it would actually be x+y>or=20. because the question just says "at least 20 pices"
okay so ill go with C
could you help me with another one
i wish i had time sorry ill be back in a little bit i have to go register for classes
okay thanks
yw!
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