What is the largest positive integer n such that 1457, 1754, and 368 all leave the same remainder when divided by n?
So we want to solve:$$1457\equiv1754\equiv368\equiv k\mod n$$It follows, then, that:$$1754-1457\equiv k-k\equiv 0\mod n$$so we know that \(1754-1457=297\) is a multiple of \(n\)
similarly we get:$$1457-368=1098\equiv 0\mod n\\1754-368=1386\equiv 0\mod n$$
We want the greatest \(n\) that satisfies the above so it follows it is merely their greatest common divisor \(\gcd(297,1098,1386)\)
So the answer would be 3?
wait but 1457-368 = 1089
good catch :p
clearly \(297=3\times99=3^3\times11,1089=1100-11=11\times99=3^2\times11^2\)
so the answer is 99! oh! I see!
and lastly \(1386=1089+297\) so \(\gcd(297,1089,1386)=\gcd(297,1089)=3^2\times11=99\)
why are you so smart? these problems would have taken me ages to figure out XD
thanks for answering my question! again >.<
haha no I just like these problems a lot ;-p they're fun. no problem!
great! ('cause i have a lot more XD)
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