Question

Let F(x)= 2x^2+x-3 and G(x)=x-1
find F(x)/G(x) and set its domain

Answer 1

G not equal zero ... is the only restriction

Answer 2

now the question is divide the functions

Answer 3

or factor f, and remove any g in it :)

Answer 4

Want me to screen shot the question?

Answer 5

x divided by x is still x correct?

Answer 6

no ... x/x = 1 as long as x not= 0

Answer 7

so it would become 2x^2+1-3?

Answer 8

if g is a factor in f; then it will have to be of them form: (x-1)(2x+k)

Answer 9

im not sure what process you are trying to do to come up with that sort of division ....

Answer 10

This is what i am working with...

Answer 11

lets narrow it down, when does g=0?

Answer 12

when x is zero?

Answer 13

lets try that assumption:

g = x-1, let x=0

g = 0-1 = -1. since -1 is not zero .. id say that is not correct

Answer 14

also, none of your options suggest that x=0 needs to be excluded

Answer 15

im on like a 7th grade level math... so i need a quick tune up.

Answer 16

when does x-1 = 0 ? this is pretty basic ....

Answer 17

there exists some number such that when you remove 1 away from it, you are left with nothing .... what is that number?

Answer 18

the number is 1

Answer 19

yes :)

so we need to make sure that "1" is not in the domain, so that should narrow it down to 2 options

Answer 20

LIke how?

Answer 21

read the options ..

Answer 22

the domain cannot include the number 1 ...

Answer 23

it cant be B or C

Answer 24

B or C is the only options that it can be, so we have to narrow it down between them

Answer 25

But B and C include 1 in the domain...

Answer 26

OHhh it says except 1 brain fart.

Answer 27

no, they include the set of all real numbers EXCEPT 1

Answer 28

<----- dummy

Answer 29

now i want you to just take a guess ... which one do you think it has to be correct: B or C?

Answer 30

B because its left in a fraction.

Answer 31

no, since the top is NOT the same as f, then that means that g would have to have been canceled out and we would have no bottom to speak about

Answer 32

Oh. so it has to be C

Answer 33

let f=gk\[\frac fg=\frac{\cancel gk}{\cancel g}=k\]

Answer 34

so yes, it has to be C

Answer 35

@amistre64 see i just figured out how to do that problem now they give me this crap..

Answer 36

Except 1?

Answer 37

if x=1, 3-1-10 is not zero

Answer 38

1+4(30) is not zero, so there are 2 values that need to be restriced .. so none of the options are correct

Answer 39

8?

Answer 40

5 times 30 is 150.

Answer 41

d is wrong simply becasue 1 is not a zero of g
a and c are wrong becuase they simply dont exclude any values

Answer 42

its B!!!

Answer 43

b is the "most" correct option but its missing one exclusion from the domain

Answer 44

all real numbers except 2 right?

Answer 45

except for 2 and -5/3

Answer 46

so B is the "correct" choice, but its not mathically correct

Answer 47

the limit of f/g exists at -5/3; but the function has no defined value there

Answer 48

Yeah i had my teacher look at it. i wont out of this stupid Gradpoint all i run in to is problems.

Answer 49

spose for instance that your GPS says that you should take a road that crosses at a bridge; the GPS is an equivalent setup for the actual road; but the actual road has the bridge out .... you would not want to take the GPS point at the bridge for the actual point of the bridge missing

Answer 50

f/g is equal to 1/(x-2) at all points EXCEPT for x=2, or x=-5/3

Answer 51

Amistre i envy you.

Answer 52

lol, thnx

Answer 53

No thank you.

Answer 54

you really are trying to teach me, i just wish i would have paid attention more to the teacher in math class than the girls. now im screwed for life.

Answer 55

:) id still pick the girls

Answer 56

lol :)