Question

if a:b=2:3 and b:c=5:3, then (a+b+c)/(a-b+c)=?
@terenzreignz

Answer 1

How do you go about this?
\[\Large \frac{a}b= \frac23\]\[\Large \frac{c}b=\frac35\]
This might help ^

Answer 2

Still no clue?

Answer 3

\[\huge \frac{a+b+c}{a-b+c}\cdot \frac{\frac1b}{\frac1b}\]
where, of course,\[\huge \frac{\frac1b}{\frac1b}=1\]

Answer 4

once again, @kryton1212
I need you to make your presence felt :P
Could you please simplify this?
\[\huge \frac{a+b+c}{a-b+c}\cdot \frac{\frac1b}{\frac1b}\]

Answer 5

(a+b+c)/(a-b+c) ???
lol

Answer 6

Well of course... -.-
But I need you to distribute the 1/b over both the numerator and the denominator...

Answer 7

what do you mean?

Answer 8

@kryton1212 ?
Stay with me here... distribute the 1/b as instructed above ^

Answer 9

i cannot get it...........

Answer 10

I'll do the numerator, you do the denominator...
\[\huge \frac{a+b+c}{a-b+c}\cdot \frac{\frac1b}{\frac1b}= \frac{\frac{a}b+\frac{b}b+\frac{c}b}{\color{red}?}\]
Do you get it now?

Answer 11

lol
?=(a/b)-(b/b)+(c/b)

Answer 12

Yes.
\[\huge \frac{\frac{a}b+\frac{b}b+\frac{c}b}{\frac{a}b-\frac{b}b+\frac{c}b}\]
Now, clearly, \[\Large \frac{b}b=1\]
What about \[\Large \frac{a}b\] and \[\Large \frac{c}b\]?

Answer 13

(a+c)/b

Answer 14

no...
I meant, what is a/b = ?
and what is c/b = ?

Answer 15

a/b=2/3
c/b=3/5

Answer 16

Yes... now
\[\huge \frac{\frac{a}b+\frac{b}b+\frac{c}b}{\frac{a}b-\frac{b}b+\frac{c}b}= \frac{\frac{2}3+1+ \frac35}{\frac23-1+\frac35}\]
I trust you can simplify it from here?

Answer 17

17/2

Answer 18

ohh, thank you very much!

Answer 19

no problem.