Question

Given triangle ABC ~ RBS, solve for y.

Answer 1

pic!!!

Answer 2

I forgot it, but across from s and above y is R.

Answer 3

Since ABC ~ RBS
\[\frac{AB}{RB}=\frac{CB}{SB} \rightarrow \frac{30+y}{30}=\frac{10+x}{10}\]
Untill unless you don't know the value of X you can't find y

Answer 4

So I solve the proportion on the right side of the equal sign to get x?

Answer 5

No, wait, sorry. That was a dumb question.

Answer 6

So how do I find x?

Answer 7

Just carry out the cross multiplication and solve it for Y in terms of X

Answer 8

I don't think I did this right...I got a really bad answer. 30x=10y....

Answer 9

\[\frac{30+y}{30}=\frac{10+x}{10} \rightarrow 10(30+y) =30(10+x)\]
i.e. \[(30+y) =3(10+x) \rightarrow 30+y = 30 +x \rightarrow y= 30+x-30 \rightarrow y=x\]

Answer 10

Hence the value of y is equal to x

Answer 11

Ohh, okay. So where do we go from there?

Answer 12

if you know the value of x so that will also be the value of y

Answer 13

You said x=y, but I'm not sure what x equals. Maybe I'm misunderstanding.

Answer 14

Thats your ans

Answer 15

do you know the value of RS

Answer 16

If yes we calculate the values of x and y both

Answer 17

RS equals 8, I think I forgot to put that.

Answer 18

Sorry about that.

Answer 19

Now we can find both x and y.pls stand by

Answer 20

Okay, thanks.

Answer 21

\[\frac{30+y}{30}=\frac{10+x}{10} =\frac{AC}{RS} \]
\[\frac{30+y}{30}=\frac{10+x}{10} =\frac{20}{8} \]
\[\frac{30+y}{30}=\frac{20}{8} \rightarrow 8(30+y) = 30 \times 20\]
\[240+8y = 600 \rightarrow 8y = 600 -240 \rightarrow 8y = 360\]
\[y = \frac{360}{8}=45 \rightarrow y=45\]
since y=x ( already proved)
therefore x=45

Answer 22

did you understand

Answer 23

Thank you so much! That really helped a lot. I really appreciate it.

Answer 24

I kind of had a vague idea that this was what I should be doing, but I was missing some pieces.

Answer 25

This is my first post, how do I do that?