Question

Find the median


http://prntscr.com/1j1rl2

and in which category does it fall?

Answer 1

I remember learning how to do this with a histogram. Did you also learn it that way, or some other method?

Answer 2

idk i am homeschooled

Answer 3

histogram = bar graph

Answer 4

ok

Answer 5

of the people or the books ?

Answer 6

?

Answer 7

is their answer choices ?

Answer 8

no

Answer 9

ok....median is the middle number
15,20,50,60,120....median is 50

Answer 10

ok

Answer 11

you better get a second opinion on this....I am not even sure if that is what the question is asking

Answer 12

@kelliegirl33, I would assume that "books read" is the independent variable, and "number of people" is the dependent variable.

If that's the case, then the median is based on the books read, and not people.

Answer 13

the question is asking to find the median and which category does it fall

Answer 14

thats all

Answer 15

ok.....books read
12 - 14, 0 - 2, 6 - 8, 3-5, 9-11
The median is 6-8

Answer 16

The number of people represents the frequency of occurrence of the particular number of books read, it is equivalent to having a distribution of
0-2 20 times, 3-5 60 times, etc.
The total (265) of the #people column is the total number of data points.
The middle number (the 133th) is the data point corresponding to the median.
Check the number of books read by the 133th person and the number of books is the median value of the data table.

Answer 17

As I mentioned earlier, the way I remember to do this involves finding areas of the rectangles... I don't know how else to describe it.

Answer 18

I should have never came to this question.....sorry sloth if I confused you. You might better listen to mathmate or sithsandgiggles

Answer 19

its ok i still don't understand

Answer 20

@kelliegirl33 It's ok, we all try to help. What is important is what you did: say so if you're not sure. Teaching is part of learning, and teaching actually helps you learn. Keep it up!

Answer 21

We are working with a one variable distribution.
If I have a distribution of number of sick days of a school term within a class of 25 people, and
10 people had 0 days
4 people had 1 day
6 people had 2 days
5 people had 3 or more days.
We find the median by first finding the number of data points (25).
We then sort the data points by the independent variable (number of sick days) as done above.
Then we find the middle data point (the 13th).
The number of sick days corresponding to the 13th point is the median.
To find the 13th data point, we start from the top:
10 < 13
10+4>13
so 13th data point is on the second line/category, so the median number of sick days is 1 day (from the second line/category).

Answer 22

so i write median is 1

Answer 23

and category is second line?

Answer 24

Yes, for the example I just gave (not your question).

Answer 25

i still don't get it

Answer 26

I'll give it a try...

The way the question is written (you're provided with grouped data), the median should probably be a number of books read. This number will be given by an interval (one of the groups of the grouped data).

The first thing to do would be to determine the frequency of data points in each interval. My earlier-drawn histogram will prove useful here:

The frequency \(f_n\) of a particular category \(n\) is given by \(f_n=b_np_n\), where I define \(b_n\) as the interval of books and \(p\) as the number of people associated with that interval.

So, \(b_1\) refers to the interval of 0-2 books read, \(b_2\) refers to the interval of 3-5 books read, and so on. Similarly, \(p_1\) refers to the number of people that read 0-2 books, and so on. For simplicity, I'll consider the length of each interval to be 2, meaning \(b_n=2\) for \(n=1,2,3,4,5\).

From the data, it's clear that \(p_1=20\), \(p_2=60\), and so on.

Make note of the fact that the area of each rectangle is given by \(f\): for the first rectangle, the base is 2 and the height is 20, so \(f_1=2\times20=40\).

Does this make sense so far? I'm drawing most of this stuff from memory.