Question

(x^2)/(x-5) - 1 = 25/(x-5)

Answer 1

\[\frac{x^2}{x-5}-1=\frac{25}{x-5}\\
\frac{x^2}{x-5}-\frac{x-5}{x-5}=\frac{25}{x-5}\\
\frac{x^2-(x-5)}{x-5}=\frac{25}{x-5}\\
\frac{x^2-x+5}{x-5}=\frac{25}{x-5}
\]
Note that \(x=5\) can't be a solution. So if \(x\not=5\), you have
\[x^2-x+5=25\\
x^2-x-20=0\]

Answer 2

Can you solve that any further?

Answer 3

Can you? It's not my problem to do.

If you want a hint, it can be factored.

Answer 4

I didn't mean you like will you do it for me. I was just asking if it was possible.

Answer 5

If I factor the first one, do I have to make it equal 0 instead of 25?

Answer 6

Nvm XD