Question

Find the center, vertices, and foci of the ellipse with equation 2x^2 + 7y^2 = 14.

Answer 1

1. Divide both sides by 14
2. Put the equation into the form:
\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\]

Answer 2

Center is (h,k)
Vertices are "a" units to the right and to the left of the center.
\[a^2-b^2=c^2\]

Answer 3

Find c.
Foci are c units to the right and c units to the left of the center.

Answer 4

after step one i got lost :(

Answer 5

What did you get after you did Step 1?

Answer 6

(2x^2)+(7y^2)/14 =1?