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Which of the following is the solution to the equation 25^2c = square root of 5^(4c + 14) ?
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\[25^{2c}=\sqrt{5^{4c+14}}\]?
the 4c+14 is not in the square root
\[25^{2c}=\sqrt{5}(4c+14)\]?
so confused
\[25^{2c}=\sqrt{5}^{(4c+14)?}\]
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yes
ok \[25^{2c}=5^{2c+7}\] make sense?
yes so far
\[(5^2)^{2c}=5^{2c+7}\]
allright
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\[5^{4c}=5^{2c+7}\] take log base 5 of both sides \[\log_5(5^{4c})=\log_5(5^{2c+7})\\4c\log_5(5)=(2c+7)\log_5(5)\\4c*1=(2c+7)*1\\4c=2c+7\\2c=7\\c=\frac{7}{2}\]
Thank you :)
np
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