Question

Lagrangian Systems

I've attached a question on Lagrangian Mechanics, if someone could explain to me how to do parts c and d, I would be really grateful!!

Thankyou

Answer 1

what class are you in? You ask such a variety of questions.

Answer 2

I'm in last year of math major

Answer 3

same here:) But what class is this for? Control theory?

Answer 4

seems odd that a mathematics major would be taking engineering math courses since mathematicians often prefer proofs over applications.

Answer 5

I disagree, most of my friends are applied mathematicians. This could be control theory, dif eq...

Answer 6

many schools only offer applied math degree.

Answer 7

This is for Intermediate Dynamics
@abb0t it depends, you can choose some of the classes you take, and there are compulsory theory ones, but i chose engineering/physics based classes

Answer 8

I was referring to pure mathematics, not applied mathematics. Pure mathematics doesn't care about the applications much,
that's what the engineers are there for. Not that there's anything wrong with them. I just dislike engineering math in general :P

Answer 9

I understand elective courses, but if hypothetically speaking I was a mathematics major, I would not have chosen this course :P

Answer 10

then you are not an applied mathematician and would not like to earn money but yet prove things that others have already proved:P

Answer 11

jokes....

Answer 12

elementary school drop out here :/

Answer 13

I've done PDEs and Linear Algebra alongside each other

Answer 14

you're crazy. the end.

Answer 15

lol, I hate applied math @abbot im just playing

Answer 16

iam in Eng physics too!! only 2nd year though :)

Answer 17

we can be engphys buddies ...

Answer 18

I prefer it when you can find pure maths solutions in a applied maths, proving somthing that;s all ready proved in that case ,can sometimes give you a tie to what would normal be viewed as pure. (like imaginary numbers and taking them as derivative from 0, instead of a solution to negative powers etc)

Answer 19

http://farside.ph.utexas.edu/teaching/336k/Newtonhtml/node82.html
only problem is that they use a slightly different convention for spherical coordinates; their \(\phi\) is your \(\theta\) and vice versa. for (c) they note that since \(L\) is independent of your \(\theta\) it follows that \(\partial L/\partial\dot\theta\) is invariant and thus our generalized momentum (corresponding to angular momentum)