Question

factor out completely:
please explain:
66x^15-22x^21+33x^14

Answer 1

first derivatives, then factoring? what kind of bizarre class is this?

Answer 2

@satellite73 She asked factorizing questions before too.

Answer 3

\[66x^{15}-22x^{21}+33x^{14}\]
each term has a common factor of \(11\) and also a common factor of \(x^{14}\)

Answer 4

start with
\[11x^{14}(something)\] and then figure out what the "something" has to be

Answer 5

I showed her how to do it,I guess she knows @Algebra2013 Do you know?

Answer 6

first term of the "something" must be \(6x\) because \(11x^{14}\times 6x=66x^{15}\)

Answer 7

I came up with:
11x^14(6x-2^7+3)

Answer 8

On the right track?

Answer 9

yeah , assumming you meant
\[11x^{14}(6x-2x^7+3)\]

Answer 10

yes, thank you very much

Answer 11

yw