Question

factor out completely:
please explain steps:
-80x^13y^4-12x^8y+6x^11y^28

Answer 1

4??

Answer 2

GCF = 4??

Answer 3

4x^8y???

Answer 4

4x^8y(

Answer 5

4x^8y(-20

Answer 6

First make it easier to read by using the equation editor\[\Large -80x^{13}y^4-12x^8y+6x^{11}y^{28 } \]

Answer 7

ok

Answer 8

\[4x ^{8y(-20x ^{5y ^{3}}}\]

Answer 9

Now look for common factors... maybe do it one at at time, first find a number that goes into all of them. Notice 80, 12 and 6 are all divisible by 2.

Answer 10

\[4x ^8y (-20x ^5y ^3\]

Answer 11

So factor out a 2 like so\[\Large 2(-40x^{13}y^4-6x^8y+3x^{11}y^{28 })\]
now look for other factors in all three terms.

Answer 12

ok one moment let me factor out 2
so I know next time.

Answer 13

remember when you pull out the 2, you have to divide each of the numbers by 2

Answer 14

ok I got the same as you. I left the exponents as is

Answer 15

what is the next step

Answer 16

\[\Large 2(-40x^{13}y^4-6x^8y+3x^{11}y^{28 })\]Now notice they all have a common factor x^8 in each. Try factoring it out.

Answer 17

\[2x^8y(-40x ^5y ^3-6+3x ^3y ^27)\]

Answer 18

I got my negatives and postives mixed up some how

Answer 19

factor out x^8\[\Large 2x^8(-40x^{5}y^4-6y+3x^{3}y^{28 })\]
then a y from each \[\Large 2x^8 y(-40x^{5}y^3-6+3x^{3}y^{27 })\]