Find sin θ if cot θ = - 2 and cos θ < 0. Answers in picture:
|dw:1375568123058:dw|
the hypotenuse is sqrt5
all you need is the hypotenuse, which you get via pythagoras in your head two squared plus one squared is four plus one is 5 |dw:1375568199484:dw|
so answer is either \(\frac{1}{\sqrt5}\) or \(-\frac{1}{\sqrt5}\) depending on what quadrant you are in
but that not an answer i thought the smae
since cotangent is negative and cosine is negative, then sine is positive
i think that is the answer
negative one divided by two - 5 square root of five divided by two square root of five divided by five these are the possible answers
@onaogh could you help?
@jdoe0001 can you help out so far satellite detrmined that the answer could be 1/sqrt5 or -1/sqrt5
but those aren't the answers
i dont think your question is correct. checked using calculator \[ cot(\theta) = -2\] find the angle: \[ \theta = cot^{-1}(-2) = \frac{1}{tan^{-1}(-2)} = -0.90322 \space rad\] now you got the angle. cosine of the angle should be less than 0 \[ cos(-0.90322) =0.61908 \] which does not satisfy the condition mentioned in the question
it's correct because it was copy pasted straight from it i ave a picture posted too
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