Question

What is PQ to the nearest tenth?

Answer 1

Ok pls wait..

Answer 2

okk,thanks

Answer 3

Seg RS is tangent to the circle with centres P and Q
So angle R = 90 degrees and angle s= 90 degrees
Draw a seg PT || RS
so PRST is a rectangle
PT=RS = 27
ST= PR=5
QT=QS-ST=9-5=4
Now in triangle PTQ, angle T = 90 degrees
so it is a right angled triangle
now by Pythagoras theorem we have
PQ^2=PT^2+QT^2 =(27)^2+(4)^2 =729+16=745
PQ^2= 745
\[PQ=27.29 \approx 27.3 \]

Answer 4

thanks,i almost had it,i just got the theorem wrong