Question

Can anybody please help me wit this?

Simplify. The result should involve exactly one ratio.

Answer 1

(1/x - x/x-1) /(2/x+1 - x-1/x)

Answer 2

\[\huge\dfrac{{\frac{1}{x}-\frac{x}{x-1}}}{{\frac{2}{x+1}-\frac{x-1}{x}}}\]

Answer 3

can you help simplify it?

Answer 4

just make it clear from your form. don't know how to do yet. XD. Do you have any idea?

Answer 5

No? so, we can do together,
separate and calculate the numerator first, make them have the same denominator, what do you get?

Answer 6

not really :/

Answer 7

I would clear the denominators what is the LCM of the two denominators?

Answer 8

x+1?

Answer 9

@RH, show me your work. I don't know how to do for the whole thing, just step by step. We can carefully check each of them, OK?

Answer 10

x+1/ x(x+1) - xˆ2+1 / x(x+1)

Answer 11

is this correct? I am not sure :(

Answer 12

Looking good so far.

Answer 13

So RH what do you get when you combined the two fractions in the numerator?

Answer 14

i dont know:(

Answer 15

Well let's focus on the numerator ok...

Answer 16

So that is\[\frac{ 1 }{ x }-\frac{ x }{ x-1 }\]
What is the LCD of those two fractions?

Answer 17

x+1?

Answer 18

No think about normal fractions what is the LCD of \[\frac{ 2 }{ 3 }-\frac{ 1 }{ 2 }\]

Answer 19

6

Answer 20

Right ... now how did you get that?

Answer 21

so you would have to multiply 2/3 by 2/2 and 1/2 by 3/3 right?

Answer 22

yes

Answer 23

@Paynesdad

Answer 24

So now to this problem what would the LCD of the top problem be using the same thought process

Answer 25

x(x+1) ?

Answer 26

Close what are the two denominators in the top part of the ratio?

Answer 27

x and x+1

Answer 28

x+1 is a denominator in the top part of the ratio?
\[\frac{ 1 }{ x }-\frac{ x }{ x-1}\]

Answer 29

1 and x, sorry

Answer 30

No those are the numerators, what are the denominators?

Answer 31

x and x-1

Answer 32

There you go...so what does the top and bottom of the first fraction need to be multiplied by?