Write the equation of the line that is perpendicular to the line y = x + 4 and passes through the point (−6, 3).

y = 3/2x − 1

y = 3/2x + 3

y = −2/3x − 1

y = −2/3x + 3

Question

Write the equation of the line that is perpendicular to the line y = x + 4 and passes through the point (−6, 3).

 y = 3/2x − 1

 y = 3/2x + 3

 y = −2/3x − 1

 y = −2/3x + 3

anonymous · Answer

What would be the slope of a line perpendicular to the line $y=x+4$?

anonymous · Answer

You'll find all the information you need to answer this question here: http://www.purplemath.com/modules/slope2.htm

anonymous · Answer

i honestly don't know. i'm not understanding  i was hoping someone could answer this step by step

anonymous · Answer

When you didn't respond, I thought you were away from your computer.
A parallel line has the same slope.
A perpendicular line has a slope that is the negative inverse.

anonymous · Answer

What is the slope of your original equation?
$y=x+4$

anonymous · Answer

$y=mx+b$ 
m = slope
b = y-intercept