what is the coordinate in quadrant 1 for 3y^2-5x^2=7 and 3y^2-x^2=23
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OpenStudy (anonymous):
I would use elimination to eliminate the y^2 term and solve for the x^2 term and then x.
OpenStudy (anonymous):
can you help me a little more than that.
OpenStudy (anonymous):
\[3y^2-5x^2=7\]
\[-\left( 3y^2-x^2=23 \right)\]
This will eliminate the y^2 term now solve for x^2 then take the squareroot to solve for x...Then find the value of y by substituting the x value into either original equation.
OpenStudy (anonymous):
so what would be the final answer then?
OpenStudy (anonymous):
Show me your work so far...
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OpenStudy (anonymous):
i dont know where to start so i have no work
OpenStudy (anonymous):
So you just wanted me to give you the answer?
OpenStudy (anonymous):
yes please
OpenStudy (anonymous):
The name of this website is openstudy.com not givemeanswers.com. If you want help, I'd be glad to. But if you just want answers, try cheaters.com.
OpenStudy (anonymous):
ok thank you anyways.
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OpenStudy (anonymous):
By the way I think I explained how you could start.