PLEASE HELP! Explain, in complete sentences, how you would completely factor 20x2 – 28x – 48 by using the grouping method. How would you check your factors for accuracy?
Group your terms together that you can factor. Then factor what is left.
First factor what's common to all three terms. 4 is common to all three terms so: 4(5x^2 - 7x - 12) Next find two numbers m and n in the following manner \(m \times n = -60\) \(m + n = -7\) Which if you think about it, you'll realize that m = -12 n = 5
Factor out the GCF of 4. 4(5x2-7x-12) Do some of the addition and subtraction to get 5x2+5x-12x-12 That's all I got. :/
Don't forget to leave the 4 in front during the factoring process: \(4(5x^2 + 5x - 12x - 12)\) Then factor by grouping inside the parentheses: \(4(5x(x + 1) - 12(x + 1))\) \(4((x + 1)(5x - 12))\) \(4(x+1)(5x - 12)\)
Now you'll be able to multiply that out to get back to the original expression.
Umm....
If you have a question or are confused you should probably state what it is you're confused about.
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