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Mathematics 17 Online
OpenStudy (anonymous):

PLEASE HELP! Explain, in complete sentences, how you would completely factor 20x2 – 28x – 48 by using the grouping method. How would you check your factors for accuracy?

OpenStudy (anonymous):

Group your terms together that you can factor. Then factor what is left.

hero (hero):

First factor what's common to all three terms. 4 is common to all three terms so: 4(5x^2 - 7x - 12) Next find two numbers m and n in the following manner \(m \times n = -60\) \(m + n = -7\) Which if you think about it, you'll realize that m = -12 n = 5

OpenStudy (anonymous):

Factor out the GCF of 4. 4(5x2-7x-12) Do some of the addition and subtraction to get 5x2+5x-12x-12 That's all I got. :/

hero (hero):

Don't forget to leave the 4 in front during the factoring process: \(4(5x^2 + 5x - 12x - 12)\) Then factor by grouping inside the parentheses: \(4(5x(x + 1) - 12(x + 1))\) \(4((x + 1)(5x - 12))\) \(4(x+1)(5x - 12)\)

hero (hero):

Now you'll be able to multiply that out to get back to the original expression.

OpenStudy (anonymous):

Umm....

hero (hero):

If you have a question or are confused you should probably state what it is you're confused about.

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