find cos theta if sin theta =-2/3 and falls in quadrant 3 HELP ASAP PLEASE
Why asap ... are you taking a quiz or something?
Do you know what SOHCAHTOA is?
|dw:1375654078551:dw| SOHCAHTOA allows us to know which two sides must be divided in order to find the sine, cosine or tangent. So for example, SOH means that \[Sin \theta = \frac{ O }{ H }\].
Since you've been told that \[Sin \theta = \frac{ -2 }{ 3 }\] then we can deduce that O = -2 and H = 3
By using pythagoras theorem we can deduce that A = \[h ^{2} = a^{2} + o^{2} \] 9 = 4 + a^2 a= sqrt{5}
however since we are of the third quadrant, A and O are always negative therefore a = \[-\sqrt{5}\]
Now we look at SOHCAHTOA again to find out that \[\cos \theta = \frac{ A }{ H }\] Which gives us \[\cos \theta = \frac{ -\sqrt{5} }{ 3 }\]
And we are done.
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