use the elimination method to solve the system of equations.
8x-4y=-2
8x+5y=7

Question

use the elimination method to solve the system of equations.
8x-4y=-2
8x+5y=7

anonymous · Answer

@Jamierox4ev3r

jamierox4ev3r · Answer

just turn everything in the first equation negative

8x-4y=-2
change that into.....
-8x+4y=2

anonymous · Answer

9y=9 @Jamierox4ev3r

jamierox4ev3r · Answer

then, if you add -8x+4y=2 and 8x+5y=7 together, the 8x and -8x will cancel each other out and you are left with....nothing O.O

jamierox4ev3r · Answer

lol just kidding thats correct @Avon XD

anonymous · Answer

so the sollution set is 0,0 or ???

anonymous · Answer

@Jamierox4ev3r

jamierox4ev3r · Answer

lol no y=1, just as u have said. Now we need to solve for x

anonymous · Answer

ok so y=1

jamierox4ev3r · Answer

8x-4(1)=-2     8x+5(1)=7
8x-4=-2         8x+5=7
   +4  +4             -5  -5
--------        ----------
8x=2              8x=2
/8 /8              /8  /8
---                 -----
x=1/4           x=1/4

jamierox4ev3r · Answer

so if x=$\large\frac{1}{4}$ and y=1, then your final answer is ($\large\frac{1}{4}, 1$)

jamierox4ev3r · Answer

Does that make sense @Avon ? :)

anonymous · Answer

nope i got lose but i c a lil bit

jamierox4ev3r · Answer

so we solved for y, then i used the y value (1) in both of the given equations in order to calculate the x value. Both of them equal $\large\frac{1}{4}$ so that means that x=$\large\frac{1}{4}$