Question

use the elimination method to solve the system of equations.
8x-4y=-2
8x+5y=7

Answer 1

@Jamierox4ev3r

Answer 2

just turn everything in the first equation negative

8x-4y=-2
change that into.....
-8x+4y=2

Answer 3

9y=9 @Jamierox4ev3r

Answer 4

then, if you add -8x+4y=2 and 8x+5y=7 together, the 8x and -8x will cancel each other out and you are left with....nothing O.O

Answer 5

lol just kidding thats correct @Avon XD

Answer 6

so the sollution set is 0,0 or ???

Answer 7

@Jamierox4ev3r

Answer 8

lol no y=1, just as u have said. Now we need to solve for x

Answer 9

ok so y=1

Answer 10

8x-4(1)=-2 8x+5(1)=7
8x-4=-2 8x+5=7
+4 +4 -5 -5
-------- ----------
8x=2 8x=2
/8 /8 /8 /8
--- -----
x=1/4 x=1/4

Answer 11

so if x=\(\large\frac{1}{4}\) and y=1, then your final answer is (\(\large\frac{1}{4}, 1\))

Answer 12

Does that make sense @Avon ? :)

Answer 13

nope i got lose but i c a lil bit

Answer 14

so we solved for y, then i used the y value (1) in both of the given equations in order to calculate the x value. Both of them equal \(\large\frac{1}{4}\) so that means that x=\(\large\frac{1}{4}\)