Question

1 + sec^2(x) +sin ^2 (x) = sec^2(x)

Answer 1

I didnt instantly see it, so looking at it, lol.

Answer 2

Are you sure that's correct?

Answer 3

Whoops, compsomehow crashed. So is this an identity or solving for x?

Answer 4

Its 1 +sec ^ 2 (x) sin^2(x) = sec^2(x) and its proving trig equations

Answer 5

Oh! Its times? You put plus o.o

Answer 6

Sorry

Answer 7

Alrighty, I'll look at it again then :P

Answer 8

Oh, this is pretty easy then. Change sec^2(x) into it's inverse. if you know what I mean.

Answer 9

Yeah 1/cos

Answer 10

Right. So this would give you:

\[1+\frac{ 1 }{ \cos ^{2}x }*\sin ^{2}x = \sec ^{2}x\]

Think you can see it from there?

Answer 11

Yeah thats what I have written down but from there I dont know how to solve

Answer 12

Well, what is sin/cos?

Answer 13

tan

Answer 14

Right. So you have 1 + tan^2(x), which is sec^2(x)

Answer 15

Ok

Answer 16

If thats it thanks and I became your fan for being helpful.

Answer 17

Glad to help :3

Answer 18

can I ask you to help on one more question ?