You roll 1 red and 1 white die. What is the probability that the number on the red die is larger than the number on the white die?
Lets solve this by considering all the cases complete the tabel if white die get number probability values red dice can take 1 1/6 2,3,4,5,6 2 3 4 5 6 complete this table to proceed
|dw:1375671333057:dw|
if the white die rolls 1 then the red die can roll 2,3,4,5,6. probability of getting a number is 1/6
rolling 1 of white and 2 on red = 1/6 x 1/6
1/36
there are 15 cases like these in total therefor 15 x 1/6 x 1/6 = 5/12
lets count
i did... using my tree. lol..
ohhh you divide 3 out of 15/36 to get 5/12 @Mousam
yup... it is better to simplify fractions to make the final answer look neat...
argeed :)
:)
\((\color{green}1,\color{red}2)\)\((\color{green}1,\color{red}3)\)\((\color{green}1,\color{red}4)\)\((\color{green}1,\color{red}5)\)\((\color{green}1,\color{red}6)\) damn i was having fun coloring....
haha it looks cool @satellite73
haha @satellite73
\((\color{green}2,\color{red}3)\)\((\color{green}2,\color{red}4)\)\((\color{green}2,\color{red}5)\)\((\color{green}2,\color{red}6)\)
keep going.... you're half way there...
haha @Mousam
\[\Huge \begin{array}l\color{red}{\normalsize\text{I}}\color{orange}{\normalsize\text{ }}\color{#9c9a2e}{\normalsize\text{l}}\color{green}{\normalsize\text{o}}\color{blue}{\normalsize\text{v}}\color{purple}{\normalsize\text{e}}\color{purple}{\normalsize\text{ }}\color{red}{\normalsize\text{c}}\color{orange}{\normalsize\text{o}}\color{#9c9a2e}{\normalsize\text{l}}\color{green}{\normalsize\text{o}}\color{blue}{\normalsize\text{r}}\color{purple}{\normalsize\text{}}\end{array}\]
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