Question

You have a 3-card deck containing a king, a queen, and a jack. You draw a random card, then put it back and draw a second random card. Calculate the probability that you draw exactly 1 king.

Answer 1

pretty small deck

Answer 2

you could draw a king on the first try, and then not a king on the second
that probability is \(\frac{1}{3}\times \frac{2}{3}=\frac{2}{9}\)

Answer 3

haha that is what i was thinking

Answer 4

or it could happen in reverse
not king, then a king
probability is the same since multiplication is commutative
it is also \(\frac{2}{9}\)

Answer 5

your final job is to add up those two numbers, aka multiply by 2

Answer 6

so 4/18 but it will just give you 2/9 after reducing

Answer 7

lol

Answer 8

huh?

Answer 9

c'mon
since when is \(\frac{2}{9}+\frac{2}{9}=\frac{4}{18}=\frac{2}{9}\) ??

Answer 10

must be some new math

Answer 11

so it would be 4/9

Answer 12

two ninths plus two ninths is four ninths
just like two apples and two apples is four apples

Answer 13

and i'm sorry jeesh, i was just confused..

Answer 14

yeah
\[\Huge \frac{4}{9}\]

Answer 15

ah don't let me give you a hard time, it is late i know

Answer 16

aww thanks @satellite73 just wanna thank you again for helping me

Answer 17

yw
got any more?

Answer 18

yeah

Answer 19

k
lets do one
math in august, ick

Answer 20

You flip 9 fair coins. Amazingly, the first 8 flips all come up heads. What is the probability that the final flip will be a head too?