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Why is [CuCl4]2- tetrahedral while Cu(NH3)4 2+ is square planar?
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?? whats this? haha high spin low spin?
sorry i dont uds
both have Cu in +2 oxidation state,but according to Valence Bond Theory,the Cu in Case of (NH3)4 a electron from 3d subshell is promoted to 4p subshell,the following eight 3d electrons pairs up in four 3d orbitals followed by dsp2 hybridization,resulting square planar,because NH3 is a moderately strong field ligand,which can cause a greater crystal field spliting of orbitals,and in a low spin complex.hope it helps.
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