Question

What is the equation of the line passing through (–3, 6) and parallel to the line y = 4x – 2 in standard form?

x – 4y = –18

x + 4y = 18

4x – y = –18

4x + y = 18

Answer 1

let the line be Y=MX+C
as its passing through(-3,6)
so 6=-3M+C
given also its parallel to line y=4x-2
and we know that 2 lines parallel have product of their slopes as -1
i.e. M*(4)=-1
or M=-1/4
so 6=-3*(-1/4)+C
C=6-3/4
C=21/4
hence equation of desired line is Y=(-1/4)X+21/4
X+4Y=21
i guess it option B

Answer 2

the line you are looking for is parallel so the slope will be the same as the original line you were given, which is slope of 4
Now we will use point slope form because we have points and a slope.
y - y1 = m(x - x1)
slope(m) = 4
(-3,6) x1 = -3, y1 = 6
y - 6 = 4(x - (-3)
y - 6 = 4(x + 3)
y - 6 = 4x + 12
y = 4x + 12 + 6
y = 4x + 18
standard form would be :
-4x + y = 18 (multiply by -1)
4x - y = -18 (divide by 4)
x - 1/4y= -18/4

I am getting something totally different ???

Answer 3

no wait....standard form is 4x - y = -18

Answer 4

so which one is the right answer ?

Answer 5

you go with who you want....but I am saying it is 4x - y = -18

Answer 6

or wait for somebody else to come and see what they get

Answer 7

I'll try that one i appriciate it ! this is like a time test n i need to pass my algebra 2 to graduate im strugglinf thank youu

Answer 8

your welcome :)