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MEDAL - Can someone help? (cscx - 1)(cscx + 1) = (______)^2
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I found that it equals cot^2(x)
@ilfy214 That is correct.
@ilfy214 u have any doubt in trigonometry please convert all other trigonometric ratios in cos or sin. it would be easier to understand
We can verify this through difference of squares and then using the identity \(\bf cot^2(x)+1=csc^2(x)\). \[\bf (\csc(x)-1)(\csc(x)+1)=\csc^2(x)-1\]Now rearrange identity:\[\bf \cot^2(x)+1=\csc^2(x) \implies \csc^2(x)-1=\cot^2(x)\]
Which then implies that:\[\bf (\csc(x)-1)(\csc(x)+1)=\cot^2(x)\]
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so would i just plug in "cos x"
cot*
@ilfy214 The bracket would look like this:\[\bf (\csc(x)-1)(\csc(x)+1)=(\cot(x))^2\]So yes, just plug in cot(x) in the brackets.
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