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Mathematics 19 Online
OpenStudy (anonymous):

MEDAL - Can someone help? (cscx - 1)(cscx + 1) = (______)^2

OpenStudy (anonymous):

I found that it equals cot^2(x)

OpenStudy (anonymous):

@ilfy214 That is correct.

OpenStudy (anonymous):

@ilfy214 u have any doubt in trigonometry please convert all other trigonometric ratios in cos or sin. it would be easier to understand

OpenStudy (anonymous):

We can verify this through difference of squares and then using the identity \(\bf cot^2(x)+1=csc^2(x)\). \[\bf (\csc(x)-1)(\csc(x)+1)=\csc^2(x)-1\]Now rearrange identity:\[\bf \cot^2(x)+1=\csc^2(x) \implies \csc^2(x)-1=\cot^2(x)\]

OpenStudy (anonymous):

Which then implies that:\[\bf (\csc(x)-1)(\csc(x)+1)=\cot^2(x)\]

OpenStudy (anonymous):

so would i just plug in "cos x"

OpenStudy (anonymous):

cot*

OpenStudy (anonymous):

@ilfy214 The bracket would look like this:\[\bf (\csc(x)-1)(\csc(x)+1)=(\cot(x))^2\]So yes, just plug in cot(x) in the brackets.

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