Question

What is the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).
Please help, struggling to finish FLVS!

Answer 1

let the line be Y=MX+C,where M is slope and C is intercept
as it passes through (6,-1) so
-1=6M+C
as it perpendicular to line 3x+y=7=>y=-3x+7 so as we know 2 lines perpendicular to each other has sum of slopes as zero.
i.e. M-3=0
or,M=3
hence -1=6*3+C
or C=-19
so the required line is Y=3X-19

Answer 2

Thank you for your help,
Here are the answers, I think the closest one is the last one ...?

y = x − 3

y = x + 17

y = −3x − 3

y = −3x + 17

Answer 3

@torilaurennn i might have done some flaws for which m not getting exact answer but I tell u a trick to reduce the no. of options.
if 2 lines are parallel then their slopes will be (-1/n)th times of other if n is 1st slope.
if 2 lines are perpendicular then their slopes will be same in magnitude opp. in sign

Answer 4

so a and b can't be the right options

Answer 5

Okay, thank you so much

Answer 6

if the lines are parallel the magnitudes of the slopes are equal
if the lines are perpendicular the product of the magnitudes of the two slopes equals to -1
above answer has mentioned it in a wrong way