sin2(x) - sin (x) +1 = 0
sin squared, correct? And completely agree with the name, btw, haha. I'll take calc over trig any day -_-
Yes
You're actually going to have no solution for this one. For these you have to pretend that sinx = just plain old x. If you do so you get: \[x ^{2}-x + 1 = 0\] You would try to factor that qith quadratic formula and, at the end, relace x with sinx. But you'll see when you try the quadratic formula, you'll come up with imaginary numbers.
Its asking to use the trig identities to solve for this question, the using to unit circle to find the answer. The example for the question before was taking sin x = cos x -> which then converts to tan x = 1, after dividing by cos x and relating it to tan x = sin x / cos x. Then finding the parts on the unit circle that have tan= 1 which would be pi/4, and 5pi/4.... there is no real good explanation for what the question is asking
I wish I could say that made any sense. I can tell you for certain there is no solution. If you tried identities, you might be running around in circles all day. This just simply isn't an identity question, it's a quadratic equation in sinx.
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