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Mathematics 15 Online
OpenStudy (anonymous):

what is the factorization of 4x2+28x+48

OpenStudy (campbell_st):

are you factoring...?

OpenStudy (uri):

4 is the GCF

OpenStudy (anonymous):

see what u can eliminate from each of the terms.. 4 seems to be a factor of all three

OpenStudy (uri):

4x2+28x+48 4(x^2+7x+14)

OpenStudy (uri):

I mean 12*

OpenStudy (campbell_st):

ok... take out 4 as a common factor \[4(x^2 + 7x + 12)\] now look at the constant term 12, find the factors of 12 that add to 7 and the factored form will be 4(x + factor 1)(x + factor 2)

OpenStudy (uri):

4(x^2+7x+12)

OpenStudy (uri):

Find a number when adding or subracting you get 7 and multiplying you get 12 So,3+4=7 3 x 4=12

OpenStudy (anonymous):

i got 4(x+3)(x+4)

OpenStudy (anonymous):

is it right?????????

OpenStudy (anonymous):

yes :)

OpenStudy (uri):

x^2+7x+12 x^2+4x+3x+12 x(x+4)+3(x+4) (x+4)(x+3)

OpenStudy (campbell_st):

thats correct... when factoring quadratics... always look at the factors of the constant that add to the coefficient of the middle term

OpenStudy (uri):

It's 4(x+4)(x+3) OR (x+3)(x+4) same thing.

OpenStudy (anonymous):

can someone help me in another problem

OpenStudy (uri):

4(x+3)(x+4)*

OpenStudy (anonymous):

-x2+2x+48

OpenStudy (uri):

Sure ask new question in a new thread,Close this one

OpenStudy (campbell_st):

well we can help you get to the answer, without providing the answer...

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