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OpenStudy (campbell_st):
are you factoring...?
OpenStudy (uri):
4 is the GCF
OpenStudy (anonymous):
see what u can eliminate from each of the terms.. 4 seems to be a factor of all three
OpenStudy (uri):
4x2+28x+48
4(x^2+7x+14)
OpenStudy (uri):
I mean 12*
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OpenStudy (campbell_st):
ok... take out 4 as a common factor
\[4(x^2 + 7x + 12)\]
now look at the constant term 12, find the factors of 12 that add to 7
and the factored form will be
4(x + factor 1)(x + factor 2)
OpenStudy (uri):
4(x^2+7x+12)
OpenStudy (uri):
Find a number when adding or subracting you get 7 and multiplying you get 12
So,3+4=7
3 x 4=12
OpenStudy (anonymous):
i got 4(x+3)(x+4)
OpenStudy (anonymous):
is it right?????????
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OpenStudy (anonymous):
yes :)
OpenStudy (uri):
x^2+7x+12
x^2+4x+3x+12
x(x+4)+3(x+4)
(x+4)(x+3)
OpenStudy (campbell_st):
thats correct... when factoring quadratics... always look at the factors of the constant that add to the coefficient of the middle term
OpenStudy (uri):
It's 4(x+4)(x+3) OR (x+3)(x+4) same thing.
OpenStudy (anonymous):
can someone help me in another problem
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OpenStudy (uri):
4(x+3)(x+4)*
OpenStudy (anonymous):
-x2+2x+48
OpenStudy (uri):
Sure ask new question in a new thread,Close this one
OpenStudy (campbell_st):
well we can help you get to the answer, without providing the answer...