Question

give me 3 points of this equation -3y= -x -6

Answer 1

Two points can be found at the x and y intersections. To make things easiest the first step would be to simplify the equation to point inter-slope form by dividing both sides by -3.
y=-(1/3)x+2
Then you would plug in 0 for x and solve, and then plug in 0 for y and solve. Don't forget the points are listed in (x,y) form. Solving those would give you two points and then a third point would be x=3 and solving for y.

Here is the three examples just plug in the solutions for the letters:

(0,y)
(x,0)
(3,y)

Answer 2

i still dont get it

Answer 3

Your given equation is:
-3y= -x -6

my first step is to divide both sides by -3:
\[-3y/-3 = (-x-6)/-3\]
then if you split it into two parts on the left side to simplify more
\[y=(-x/-3)+(-6/-3)\]
the negatives cancel out for the -6/-3
\[y=-(x/3)+2\]

now you can plugin numbers to find the points:
first we will do x=0 to find a value for y.

y=-(0/3)+2
the 0/3=0
leaving only a 2
so y=2
that makes the first point in x,y form (0,2)

let me know if you still need help

Answer 4

can you help with the second an third one?

Answer 5

While that may have made it look a little harder than it should, there is no such concept as THE second and third one, they all depend on you, actually.

Let's run that by you again:
-3y= -x -6

To get ANY point on this line, pick any three DIFFERENT values for x.
Say x = 0
Replace x with 0.
-3y= -0 -6
And just solve for y.
-3y = -6
Divide both sides by -3, and you should get
y = -6/-3
y = 2

Hence, when x = 0, y = 2.
Therefore, the point (0,2) is on the line.

Answer 6

can you do that with a different x like 2?

Answer 7

Any value for x, in fact.
So, pick another value for x, one that isn't 0.

Answer 8

2

Answer 9

Fine...
-3y= -x -6
Replace x with 2.
-3y = -2 - 6
and solve for y.

Answer 10

thats what i dont get is solving for y

Answer 11

You can't solve linear equations in one variable? D:

Answer 12

no i do i just dont know what to do

Answer 13

Well, then solve
-3y = -2 - 6
as though it were a linear equation, then.

Answer 14

Heck, it is....

Answer 15

what??

Answer 16

You said you can solve linear equations in one variable... then solve
-3y = - 2 - 6
Because that ^
IS a linear equation in one variable.

Answer 17

what do i do first?

Answer 18

Let me run the first one by you again... with detailed steps...

Answer 19

\[\large -3y = -x -6\]Now suppose x = 0.
Replace x with 0.
\[\large -3y = -\color{red}0 - 6\]

Now simplify -0-6, they are just numbers which may simply be added or subtracted...
\[\large -3y = \color{green}{-6}\]
Now divide both sides by -3.
\[\large \frac{-3y}{\color{blue}{-3}}=\frac{-6}{\color{blue}{-3}}\]


This cancels:\[\large \frac{\cancel{-3}y}{\color{blue}{\cancel{-3}}}=\frac{-6}{\color{blue}{-3}}\]

Leaving you with
\[\color{red}{\huge y = 2}\]

And so, the point \[\huge (0,2)\] is one point on your line.

Now please do the same, starting from x = 2.