http://tinypic.com/r/zumj53/5 In the following triangle, find the values of the angles B and B', which are the best approximations to the solutions of this ambiguous case. A. B = 70.05 or B' = 109.95 B. B = 65 or B' = 115 C. B = 56.2 or B' = 123.8 D. B = 67 or B' = 102.2
Okay so... I have no idea how to do ambiguous cases.
oh wait. thats the wrong one!
i am totally confused you have two angles, which means you know the third for sure there is nothing ambiguous about it
ambiguous is where you know two sides and one angle then there could be an acute or obtuse triangle, depending
I was looking at the wrong graph! I'm good now
oh lol find B using law 'o sines, then B'= 180 - B you good right?
Let me try this out...
k
Thinking! 23.95 and ....
156.05! But they aren't choices
i guess i should see what i get if i am to check it give me a sec
The choices are in the 50s to 70s?
Let me try again
\[\frac{\sin(45)}{16.5}=\frac{\sin(B)}{22}\iff\frac{ 22\sin(45)}{16.5}=B\]
oops i mean \[\frac{22\sin(45)}{16.5}=\sin(B)\]
and so \(B\) is the arcsine of all that mess
lets try it
I can't reverse sine on the calculator. So i'm kinda stuck?
i get \(70.53\)
lol of course you can!
i mean if you are on a computer you can http://www.wolframalpha.com/input/?i=arcsin%2822sin%2845%29%2F16.5%29
OH! Wolfram. Gotcha
i cant remember the last time i used a calculator maybe to find a percent or something, certainly not for this kind of work so twentieth century
The closet to 70.53 is A... LOLZ! I've used wolfram before, but I forgot the same. Its so good!!!
yeah, you probably didn't even have to write what i wrote to get the answer
WOAH! You're already at 100! jealous.
already lol only been a few years and countless hours
Join our real-time social learning platform and learn together with your friends!