Question

HELP YOU GUYS! MEDAL WOULD BE GIVEN OUT FOR ANSWER & CORRECT EXPLANATION.

Answer 1

You have : \(\sqrt{a}= c\sqrt{d}\)

Square both sides. What you get?

Answer 2

\[\sqrt{a}^2 and c \sqrt{d}^2\]

Answer 3

Yep, so what is : \(\sqrt{a} ^2 \) ?

Answer 4

a?

Answer 5

Good, it is "a".

Now what is : \((c\sqrt{d})^2\)

Answer 6

would it be just cd?

Answer 7

No no , see : \((c \sqrt{d})^2 = (c)^2 ( \sqrt{d})^2 = c^2 d\)

Got it?

Answer 8

but wait thats not one of the answers i see how you ended with that will kinda for the c2 one

Answer 9

We have not arrived to the answer yet.

Answer 10

We have to find : \(\sqrt{a^2 b^4}\) = \(a b^2\)

Answer 11

wait dont we break it down to two parts? so \[\sqrt{a}^2 & \sqrt{b}^4\]

Answer 12

Now as , a = \(c^2 d\) and \(\sqrt{b} = d\sqrt{c}\)

We need to find \(b^2\) now. Since : \(\sqrt{b} = d \sqrt{c}\) ; \((\sqrt{b})^2 = (d\sqrt{c})^2 \) ; Can you simplify it ?

Answer 13

@mary.rojas

Answer 14

Yeah , you are right. Breaking it to two parts : \(\sqrt{a}^2 \times \sqrt{b^4}\) . Now : \(\sqrt{a^2} = a \) and \(\sqrt{b^4} = b^2 \)

Answer 15

so now the b needs to be b^4 right

Answer 16

@mathslover

Answer 17

i think its c^2D^3 but im not sure though that was my first answer :(

Answer 18

@mathslover im between C & A? but im heading more to C because it has the square root & i think it might make it turn into b^4

Answer 19

@satellite73 @KingGeorge

Answer 20

i need help big time! i think its C though i need a clarification!

Answer 21

@satellite73 @thomaster @KingGeorge @yahya90 @nincompoop

Answer 22

help!!!!!!!!

Answer 23

HELP!