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Mathematics 19 Online
OpenStudy (anonymous):

The measurement of the height of 600 students of a college is normally distributed with a mean of 175 centimeters and a standard deviation of 5 centimeters. What percent of students are less than 170 cm in height? a. 0.5 c. 15.5 b. 2.0 d. 16.0

OpenStudy (amistre64):

what process comes to mind?

OpenStudy (anonymous):

idk elimination

OpenStudy (anonymous):

is it standard deviation from the mean---the bell curve \[sd\pm mean\]

OpenStudy (amistre64):

your asking a stats question, not a system of equations question :/

OpenStudy (amistre64):

you might want to go read over your material to get some sort of foundational understanding of this .....

OpenStudy (amistre64):

.. and it looks like they are using the empirical rule in the solution process as opposed to something more exacting.

OpenStudy (anonymous):

well i looked over and still dont get it

OpenStudy (anonymous):

Well I would suggest using a z-scores. You want to know P(x<170), right?

OpenStudy (anonymous):

@baseballer20142

OpenStudy (anonymous):

right

OpenStudy (anonymous):

Ok so let's convert the x<170 into a z score so that we can find P(z<something) and we can use a chart or you calculator to look up the probability.

OpenStudy (anonymous):

so how do we turn 170 into a z-score?

OpenStudy (anonymous):

flipped it idk

OpenStudy (anonymous):

Come on in your book there is a formula that involves z, \[ \mu\] and \[ \sigma \] and probably x. You need to find that formula.

OpenStudy (anonymous):

If you look in the index for z-score it will probably direct you to a page.

OpenStudy (amistre64):

it might be called standard score these days ....

OpenStudy (amistre64):

lol, under standard score mine says: see z score

OpenStudy (anonymous):

@baseballer20142 DO you want help or just an answer?

OpenStudy (anonymous):

its normal distribution stuff and the answer please

OpenStudy (anonymous):

Ok then you are on the wrong website. This is for studying and learning not just getting answers. I would be happy to help you, but you need to participate in your learning...not just be spoon fed answers.

OpenStudy (anonymous):

This problem is not terribly hard but you need to find the formula for converting into z scores.

OpenStudy (anonymous):

@baseballer20142 ??

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