solve
two things we need to set up the equation of line: slope and y intercept we know that point of interception of those equations is point which our line passes through. Can you find that point?
can you solve that system of equations?
yes
x=1/5 y=3/5
correct. substitute them in equation in general form: y=mx+b so you get \[\frac{ 3 }{ 5 }=m\frac{ 1 }{ 5 }+b\] one equation with two unknows- we can't solve it. we need another one |dw:1375805496592:dw| what is area of triangle in terms of x and b(y intercept)?
3/8=(1/2) * (1x/5) *(3y/5)
no the equation will look like this: \[\frac{ 3 }{ 8 }=\frac{ 1 }{ 2 }b*x\] and x is the coordinate when y=0 so 0=mx+b x=-m/b substitute that and you have \[\frac{ 3 }{8 }=-\frac{b ^2}{ 2m }\]
an this is second equation, now you can solve for b and m (two b's and m's you should get, and so two equations of lines)
so what are those equations?
if you substitute m from second equation to first you'll have: \[m=-\frac{ 4b^2 }{ 3 }\] \[\frac{ 3 }{5}=\frac{ 1}{ 5 }*(-\frac{ 4b^2 }{ 3 })+b\] can you solve this quadratic equation?
but @Fifciol when x = -m/b value is put into (3/8) = (1/2) *b* x we get -m = 3/4 plse see
yes, this would be one of your solutions
okay
i got m= -3/4
and b = 3/4
now, what to do next
so your first equation is y=-3/4x + 3/4
okay
this is the answer
but there is another one
\[\frac{ 3 }{ 5 }=-\frac{ 4b^2 }{ 15 }+b\] one of the solutions of this equation is 3/4 but it's quadratic equation. There must be another one
so on solving this , i will got another answer i mean another equation of st. line
yup
i got b = 3/4 and 3
correct
so for b=3 what is m?
m=-12
yes so your 2nd line equation looks now like this: y=-12x + 3
these two equations are the answer for your question
@Fifciol thank u so much
yw :)
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