Question

Integration Help Required!!There's a second limiting function attachment as u go down!!Need help with that also!!

Answer 1

Attachmnt

Answer 2

@amistre64 ,@ash2326 @abb0t Help

Answer 3

@ash2326

Answer 4

@l

Answer 5

@litchlani

Answer 6

@Luigi0210

Answer 7

@KingGeorge

Answer 8

Correct me If I am wrong.......If not post the ans u get....

Answer 9

\[2\int\limits_{a}^{b} \sec^2(x)dx + 3 \int\limits_{a}^{b}\tan(x)\sec(x)dx...\]

Answer 10

then use FToC pt. II to evaluate from a<x<b where a = 0 and b = \(\frac{ \pi}{4}\)

Answer 11

I need the answer to check with what I got!!

Answer 12

I did this in my head, but I got 1+√2 -1, so √2?

Answer 13

2-3*2^1/2+c

Answer 14

I got this

Answer 15

\(\sqrt{2}\)

Answer 16

Ans given is \[3\sqrt{2}-1\]

Answer 17

yeah. I 4got to distribute the 2 and the 3.

Answer 18

So can u post ur work??

Answer 19

\(2[1-0] + 3[\sqrt{2} -1]\)

Answer 20

Ok.....So u shud take the constant out,operate on the definite values then multiply with the constants???

Answer 21

Tnx for the help abb0t,,,Appreciate it!!

Answer 22

THERE IS NO CONSTANT FOR DEFINITE INTEGRALS!

Answer 23

So wat are 2 and 3??

Answer 24

I'm talking about the "C"

Answer 25

That I know.I meant 2 and 3!!

Answer 26

yes, it's basic algebra, distribute, and do the arithmetics. Your answer is \(3\sqrt{2}-1\)

Answer 27

Ya can u help me with one more??@abb0t

Answer 28

@abb0t

Answer 29

Just tell me how to proceed.Rest I'll do!1

Answer 30

Limiting function!

Answer 31

First of all, you can start by eliminating one of the terms. Factor the denominator on the first limit function. You should know how to factor from basic algebra.
\[\lim_{x \rightarrow 1} \frac{ (\sqrt{x}-1)-x (2x-3) }{ (x+1)(2x-3) }...\]

Answer 32

yes

Answer 33

Same with the \(2^{nd}\) one. You can eliminate one of the denominators and numerator.

Answer 34

@Zarkon