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Mathematics 14 Online
OpenStudy (highschoolmom2010):

Find the value of each variable. If your answer is not an integer, express it in simplest radical form.

OpenStudy (highschoolmom2010):

OpenStudy (highschoolmom2010):

\[h=\sqrt{2}*leg\] \[h=\sqrt{2}*\sqrt[2]{3}\]

OpenStudy (highschoolmom2010):

this is where im confused

OpenStudy (mathstudent55):

Again, a 30-60-90 triangle, so we have a \(1 : \sqrt{3} : 2 \) ratio of sides.

OpenStudy (highschoolmom2010):

so i have 2sqrt 3 for the side 1

OpenStudy (mathstudent55):

No. Be careful. The long leg is 2sqrt(3). In the ratio, the long leg is sqrt(3)

OpenStudy (mathstudent55):

Ratio: 1 : sqrt(3) : 2 Your triangle: y : 2sqrt(3) : x

OpenStudy (mathstudent55):

Since the long leg is sqrt(3) times longer than the short leg, the short leg is sqrt(3) times shorter than the long leg. Divide the long leg by sqrt(3) to get the short leg, x. Then multiply the short leg by 2 to get the hypotenuse, y.

OpenStudy (zale101):

longer leg=√3*shorter leg 2√3=y√3

OpenStudy (zale101):

\[\frac{ 2√3}{ √3 }*\frac{ √3}{ √3 } simplify \]

OpenStudy (anonymous):

\[x\text{=}2 \sqrt{3}\text{Sec}[30{}^{\circ}]\text{=}4\]\[y=2 \sqrt{3}\text{Tan}[30{}^{\circ}]=2 \]

OpenStudy (highschoolmom2010):

\[\frac{ 2\sqrt{3} }{ 2 }=\sqrt{3}\]

OpenStudy (highschoolmom2010):

@robtobey what is that

OpenStudy (highschoolmom2010):

@radar @hobbs978 @jdoe0001 @nincompoop @Psymon @thomaster @timo86m please can someone help me here

OpenStudy (anonymous):

i dont think she know trig :)

OpenStudy (anonymous):

its a 30 60 90 like math student said so solve the ratio :D

OpenStudy (highschoolmom2010):

but i get to |dw:1375832123497:dw| and no one wants to say if i am going right or not and what to do next

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