find the zeros of the function f(x) = 4x3 - 12x2 - 40x
Any ideas?
not really the choices I have -5 and 2 5 and -2 0, 5, and -2 0, -5, and 2
@skullpatrol Do you have this?
@Paynesdad You can take it pal :)
Laren the best bet is to try to factor if you can... always start by looking for common factors.
$$\Huge 4x^3 - 12x^2 - 40x$$
Remember to find zeros you set the function = 0 and solve for x ... right @lauren9695
yes
So the equation is \[4x^3-12x^2-40x=0\] Do you see any common factors in the left hand side?
@lauren9695
yes theyre all by a common factor of 4
Ok and something else too
ummm I cant think of anything else
Well don't just think about numbers consider variables too.
ohhh they have a variable of x
Right so go ahead an factor the left side and show me what you have.
@lauren9695
wouldn't you the quadratic formula
You can't yet because it is not a quadratic equation.... just factor the 4x out first and show me what you have ... we can go from there.
@lauren9695 Hello...I will be leaving soon so I need you to respond a little quicker if you want my help.
sorry my computer froze on me and if you factor out the 4x you would 3x^2+10x
No there would still be three terms...What is left when you factor 4x^2 out of the 4x^3 term?
oh 4x
No if you factor 4x out of 4x^3 you will not be left with 4x ...try again.
wouldn't it be x^3
Not if you factored out an x too!
$$\Huge 4x^3 - 12x^2 - 40x$$
\[4x^3-12x^2-40x=4x\left(??-3x-10\right)\]
Notice when I factored I didn't just lose or get rid of the 4x ... it just came out infront of the parentheses... but what is the ?? term @lauren9695
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