How many grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl? Mg (s) + 2 HCl (aq) yields MgCl2 (aq) + H2 (g)
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thomaster (thomaster):
\(\large\sf Mg+2HCl \to MgCl_2+H_2\)
First calculate the amount of moles HCl, Do you know how to do that?
OpenStudy (anonymous):
I am completely lost.
thomaster (thomaster):
Do you know what 5.0M HCl means?
OpenStudy (anonymous):
Yeah
thomaster (thomaster):
well?
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OpenStudy (anonymous):
I know what it means but not the answer.
thomaster (thomaster):
It means 5 mol per liter
We have 4.8 liter, how many moles do we have?
OpenStudy (anonymous):
29?
thomaster (thomaster):
5*4.8= 24
So we have 24 mol HCl
Do you know the ratio of the reaction?
OpenStudy (anonymous):
oops clicked the wrong number on the calculator. No i dont know the ratio
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thomaster (thomaster):
1 mol Mg reacts with 2 mol HCl to produce 1 mol MgCl2 and 1 mol H2
So 1:2;1:1
For every mole Mg, 2 moles HCl are used
We have 24 mol HCl, how many moles Mg are used?
OpenStudy (anonymous):
12
thomaster (thomaster):
That's correct
Now we only have to convert that to grams
To do this, multiply with the molar mass of magnesium
OpenStudy (anonymous):
12x24
288?
thomaster (thomaster):
Almost, the molar mass of Mg is 24.305
So that would be 12*24.305= 291.66 gram
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OpenStudy (anonymous):
Ok, then what?
thomaster (thomaster):
That is the answer :)
thomaster (thomaster):
the amount of grams Mg that will react with 24 mol HCl