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Chemistry 22 Online
OpenStudy (anonymous):

How many grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl? Mg (s) + 2 HCl (aq) yields MgCl2 (aq) + H2 (g)

thomaster (thomaster):

\(\large\sf Mg+2HCl \to MgCl_2+H_2\) First calculate the amount of moles HCl, Do you know how to do that?

OpenStudy (anonymous):

I am completely lost.

thomaster (thomaster):

Do you know what 5.0M HCl means?

OpenStudy (anonymous):

Yeah

thomaster (thomaster):

well?

OpenStudy (anonymous):

I know what it means but not the answer.

thomaster (thomaster):

It means 5 mol per liter We have 4.8 liter, how many moles do we have?

OpenStudy (anonymous):

29?

thomaster (thomaster):

5*4.8= 24 So we have 24 mol HCl Do you know the ratio of the reaction?

OpenStudy (anonymous):

oops clicked the wrong number on the calculator. No i dont know the ratio

thomaster (thomaster):

1 mol Mg reacts with 2 mol HCl to produce 1 mol MgCl2 and 1 mol H2 So 1:2;1:1 For every mole Mg, 2 moles HCl are used We have 24 mol HCl, how many moles Mg are used?

OpenStudy (anonymous):

12

thomaster (thomaster):

That's correct Now we only have to convert that to grams To do this, multiply with the molar mass of magnesium

OpenStudy (anonymous):

12x24 288?

thomaster (thomaster):

Almost, the molar mass of Mg is 24.305 So that would be 12*24.305= 291.66 gram

OpenStudy (anonymous):

Ok, then what?

thomaster (thomaster):

That is the answer :)

thomaster (thomaster):

the amount of grams Mg that will react with 24 mol HCl

OpenStudy (anonymous):

Thank you

thomaster (thomaster):

You're welcome

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