How many grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl? Mg (s) + 2 HCl (aq) yields MgCl2 (aq) + H2 (g)
\(\large\sf Mg+2HCl \to MgCl_2+H_2\) First calculate the amount of moles HCl, Do you know how to do that?
I am completely lost.
Do you know what 5.0M HCl means?
Yeah
well?
I know what it means but not the answer.
It means 5 mol per liter We have 4.8 liter, how many moles do we have?
29?
5*4.8= 24 So we have 24 mol HCl Do you know the ratio of the reaction?
oops clicked the wrong number on the calculator. No i dont know the ratio
1 mol Mg reacts with 2 mol HCl to produce 1 mol MgCl2 and 1 mol H2 So 1:2;1:1 For every mole Mg, 2 moles HCl are used We have 24 mol HCl, how many moles Mg are used?
12
That's correct Now we only have to convert that to grams To do this, multiply with the molar mass of magnesium
12x24 288?
Almost, the molar mass of Mg is 24.305 So that would be 12*24.305= 291.66 gram
Ok, then what?
That is the answer :)
the amount of grams Mg that will react with 24 mol HCl
Thank you
You're welcome
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