solve sin^2(theta)=2sin(theta) +3
If you take x = sin(theta) you could rewrite that as x^2 = 2x + 3 and then solve for x and plug back for sin(theta)
so x will equal 3,-1?
Yup, now you just have to plug back in sin(theta) and get theta all by it's self.
so itll be 3^2=2(3)+3 like that?
Well you already have x = 3 and since you substituted sin(theta) for x you still need to find out what theta is You have right now that x = 3 and -1 so then sin(theta) would also = 3 and -1
so the answer will be theta = 3, -1
well you still have sin(theta), you can not just get rid of the sine function. If you use algebra arcsin(sin(theta)) = theta So you just have to use that logic to solve for theta in the equations you already have. sin(theta) = 3 & sin(theta) = -1
thanks
Your welcome!
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