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OpenStudy (anonymous):
If a gas occupies 1733 cm3 at 10.0C at what temp will it occupy 950 cm3? Assume that pressure remain constant.
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OpenStudy (aaronq):
PV=nRT
if P, n and R are constant, then
\[\frac{ V _{1} }{ T _{1} }=\frac{ V _{2} }{ T _{} }\]
OpenStudy (anonymous):
1733/10.0=950/?
OpenStudy (aaronq):
T needs to be in Kelvin
OpenStudy (anonymous):
How do I convert to K
OpenStudy (aaronq):
lol 0 Kelvin = -273.15 celsius
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OpenStudy (anonymous):
-2730.5
OpenStudy (anonymous):
-2731.5
OpenStudy (aaronq):
no,
10.0C + 273.15 C = 283.15 K
OpenStudy (anonymous):
1733cm3/283.15K?
OpenStudy (aaronq):
yep
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OpenStudy (aaronq):
1733/283.15=950/? ->T2=950*283.15/1733
OpenStudy (anonymous):
155.218
OpenStudy (anonymous):
Kcm3?
OpenStudy (aaronq):
T2=950 cm^3*283.15 K/1733cm^3
the cm^3's will cancel each other out.
OpenStudy (anonymous):
would it 155.217K
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OpenStudy (aaronq):
ye
OpenStudy (anonymous):
thank you so much;D
OpenStudy (aaronq):
no problem, dude!
OpenStudy (anonymous):
I'm a dudett lol
OpenStudy (aaronq):
oh mah badd, it says 'MAN' in your name :P
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OpenStudy (anonymous):
lol its okay part of my last name lol ;D everyone thinks that Lol
OpenStudy (aaronq):
ohhh ok haha
OpenStudy (anonymous):
thanks for your help don't have a chem book makes it hard to work on
OpenStudy (aaronq):
no problem, really. If you want i can give you a link and you can download a pdf
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