Question

how do i show by differentiation that P=L/(1+Ce^-kt) is a solution to the equation dP/dt = kP * (L-P)/L

Answer 1

By differentiation? Hmm ok let's see...\[\large P=\frac{L}{1+Ce^{-kt}}\]Let's rewrite this, using rules of exponents.\[\large P=L(1+Ce^{-kt})^{-1}\]This will allow us to apply the product rule.

Answer 2

Oh you this being answered somewhere else... not sure why you posted this 3 times.. :(
Ok nevermind..