Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Evaluate

OpenStudy (anonymous):

|dw:1375883166296:dw|

OpenStudy (anonymous):

i guess it is n=1 at the bottom ?

OpenStudy (anonymous):

so you can split it into two terms : sum of (-n-4) = sum of (-n) - 4*6 = - sumof (n) - 24

OpenStudy (anonymous):

\[\sum_{n=1}^{6}(-n-4)\]

OpenStudy (anonymous):

now there is formula for sum of first n terms ..

OpenStudy (anonymous):

its n-1

OpenStudy (anonymous):

so what is the first number of n or n-1

OpenStudy (anonymous):

the sum goes from ? to 6

OpenStudy (anonymous):

4 to 6

OpenStudy (anonymous):

|dw:1375884690265:dw|formula

OpenStudy (anonymous):

I'm a bit confused now. What is this formula?

OpenStudy (anonymous):

wait so the sum is from n-1=4 to 6 ?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

so lets change the index call n-1 = t so the sum goes from t=4 to t =6 and in the sum you have -t-5

OpenStudy (anonymous):

so if you sum -5 three times you get -15

OpenStudy (anonymous):

no as for the -t you have - (4+5+6) = -15

OpenStudy (anonymous):

-15-15 = -30

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

yw i hope i understood it correctly and it is fine

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!