A plane travels from Orlando to Denver and back again. On the five-hour trip from Orlando to Denver, the plane has a tailwind of 40 miles per hour. On the return trip from Denver to Orlando, the plane faces a headwind of 40 miles per hour. This trip takes six hours. What is the speed of the airplane in still air?
you can put say \(r\) as the rate, and therefore the rate with the wind is \(r+40\) and the rate against it is \(r-40\) then as distance is rate times time, you know \[\frac{D}{r+40}=4\] or \[D=4(r+40)\] similarly \[D=6(r-40)\] since the distance is the same in both equations, solve \[4(r+40)=6(r-40)\] for \(r\)
you good from there?
Explain more please sorry
explain how to solve the equation, or explain where the equation came from?
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