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Mathematics 22 Online
OpenStudy (anonymous):

A plane travels from Orlando to Denver and back again. On the five-hour trip from Orlando to Denver, the plane has a tailwind of 40 miles per hour. On the return trip from Denver to Orlando, the plane faces a headwind of 40 miles per hour. This trip takes six hours. What is the speed of the airplane in still air?

OpenStudy (anonymous):

OpenStudy (anonymous):

you can put say \(r\) as the rate, and therefore the rate with the wind is \(r+40\) and the rate against it is \(r-40\) then as distance is rate times time, you know \[\frac{D}{r+40}=4\] or \[D=4(r+40)\] similarly \[D=6(r-40)\] since the distance is the same in both equations, solve \[4(r+40)=6(r-40)\] for \(r\)

OpenStudy (anonymous):

you good from there?

OpenStudy (anonymous):

Explain more please sorry

OpenStudy (anonymous):

explain how to solve the equation, or explain where the equation came from?

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