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Determine f^-1(x) for f(x)= 3 times the square root of x-3.
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\[3\sqrt{x-3}\] correct?
yes! sorry, I didn't know how to do that.
You can click the equation button below the chat box thingy xD But alright, so if you need f inverse, then you need to switch x and y in your equation and then resolve for y. So basically you have: \[y = 3\sqrt{x-3}\] which becomes \[x = 3\sqrt{y-3}\] Do you know how to solve for y from here?
I was pretty sure I did. I thought that since it's a cube root, you raise the whole function to the power of 3 to get rid of the cube root so it'd be x=(y-3)^3 right?
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