Question

Vinegar has a density of 1.0056 g/cm3. What is the mass of 7 L of vinegar?

Answer 1

Solve the problem in two steps:
1) rewrite the density to the unit gram/L
2 )
\[\large \rho = \frac{ m }{ V } \to m=\rho ~ V\]

Answer 2

rho (the p like thing) is the density.
m the mass
V the volume

Answer 3

I did all that and got 7039.2 am I doing something wrong

Answer 4

Looks right to me:
\[\large 1.0056 \frac{ g }{ cm ^{3} }*1000 \frac{ cm ^{3} }{ dm ^{3} }=1005.6 \frac{ g }{ dm ^{3} }=1005.6 \frac{ g }{ L }\]
\[\large 1005.6 \frac{ g }{ L } * 7 L \approx 7039 g\]

Answer 5

I put that into my webassign homework and it marks it wrong, I tried 7039.2, 7039, and 7040

Answer 6

Okay.
Funny, but I'm 100% sure on my calculation, the conversion should also be right:
Lets go it through:
\[\large 1 dm ^{3}=1 L\]
This is per definition.
\[\large 1000 ~ cm ^{3}=1 ~ dm ^{3} \to 1=1000 ~ \frac{ cm ^{3} }{ dm ^{3} }\]
Mathmatical axiom that allow us to multiply with 1:
\[1*x=x ~ ~ ~ \forall x\]

Answer 7

Are you checking your significant figures?

Answer 8

I've tried that as well and it is still wrong

Answer 9

Well still weird. Think it is a bug of some kind.

Answer 10

Try 7000

Answer 11

If you can that is*

Answer 12

That was it! Thanks

Answer 13

Awesome. Remember, because 7 was a value, your significant figures became 1. so 7039 would become 7000.

Answer 14

Emmm 7000 have 4 signaficant figures, the zeros too are significant.

Answer 15

If you want only 1 significant figure we should say \[7*10^{3}\]

Answer 16

But I do not have a period after the 7000

So it has 1 sig-fig ;o